meson: consistently use feature['foo']

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Since the previous commit introduced the notion of a features dictionary
that conveniently tells us whether or not to use a feature in a simple
yes/no, we can make use of this everywhere in the build. Instead of
doing something like 'if foo.()', change it to 'if feature['foo']
instead. This enforces a consistent standard instead of having a lot of
different possible combinations of booleans that may or may not do
something.

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Dudemanguy committed 2022-08-15 14:14:44 +00:00

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commit 1835dfc05c

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+246 -267

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meson.build

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